FINALTERM
EXAMINATION
Fall 2009
CS601- Data Communication
Ref No: 1139834
Time: 120 min
Marks: 85
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Student Info
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Student ID:
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BC080402322
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Exam Date:
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For Teacher's Use Only
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Question No: 1 (
Marks: 1 ) - Please choose one
An unauthorized user is a
network ___________ issue.
► Performance
► Reliability
► Security
► All of the given
Question No: 2 (
Marks: 1 ) - Please choose one
Which is not an element of
protocol
► semantics
► timing
► communication service module
Question No: 3 (
Marks: 1 ) - Please choose one
_______ is a multipoint
topology.
► Ring
► Mesh
► Tree
► Bus
Question No: 4 (
Marks: 1 ) - Please choose one
Unidirectional traffic
movement is overcome by dual ring technology.
► True
► False
Question No: 5 (
Marks: 1 ) - Please choose one
Physical layer define
characteristics of interface between device and _________
► transmission medium
► another device
► another peer physical layer at other side
► modem
Question No: 6 (
Marks: 1 ) - Please choose one
________ layer deals with syntax
and semantics of information exchange.
► presentation
► session
► application
► physical
Question No: 7 (
Marks: 1 ) - Please choose one
To allow access to network
resources is the function of ___________
► application layer
► physical layer
► network layer
Question No: 8 (
Marks: 1 ) - Please choose one
Time domain plot show changes
in signal phase with respect to time.
► True
► False
Question No: 9 (
Marks: 1 ) - Please choose one
In 8QAM each signal shift or
one baud represents ______.
► 4 bits
► 2 bits
► 5 bits
► 3 bits
Question No: 10 (
Marks: 1 ) - Please choose one
Modulation of an analog
signal can be accomplished through changing the ___________ of the carrier
signal.
► amplitude
► frequency
► phase
► all of the given
Question No: 11 (
Marks: 1 ) - Please choose one
EIA 449 provides much better
functionality than EIA ________
► 232
► 223
► 262
► 222
Question No: 12 (
Marks: 1 ) - Please choose one
Which of the following is an
example of ITU-T modem standards:
► T-series
► X-series
► N-series
► V-series
Question No: 13 (
Marks: 1 ) - Please choose one
Traditional modems are wide
spread now to a data rate of __________.
► 56 Kbps
► 72 Kbps
► 42 Kbps
► 96
Kbps
Question No: 14 (
Marks: 1 ) - Please choose one
In case of uploading at the
switching station, data is converted to digital signal using ___________.
► TCP
► PCM
► ICP
► TDM
Question No: 15 (
Marks: 1 ) - Please choose one
The RG number gives us
information about ________.
► Twisted pairs
► Coaxial cables
► Optical fibers
► all of the given
Question No: 16 (
Marks: 1 ) - Please choose one
The _________ is an
association that sponsors the use of infrared waves.
► IrDA
► EIA
► FCC
► PUD
Question No: 17 (
Marks: 1 ) - Please choose one
Optical fibers are defined by
the ratio of the ___________ of their core to the diameter of their cladding.
► Diameter
► Radius
► Length
► Width
Question No: 18 (
Marks: 1 ) - Please choose one
The section of EM spectrum
defined as Radio Communication is divided into _____ ranges called BANDS.
► 8
► 10
► 5
► 6
Question No: 19 (
Marks: 1 ) - Please choose one
Radio wave transmission
utilizes ___________ different types of propagation.
► Four
► Three
► Two
► Five
Question No: 20 (
Marks: 1 ) - Please choose one
The VLF and LF bands use
_________ propagation for communications.
► Ground
► Sky
► Line of sight
► Space
Question No: 21 (
Marks: 1 ) - Please choose one
In __________ propagation,
low-frequency radio waves hug the earth.
► Ground
► Sky
► Line of Sight
► Space
Question No: 22 (
Marks: 1 ) - Please choose one
dB is ____________ if a
signal is amplified.
► Negative
► Positive
► Null
► Zero
Question No: 23 (
Marks: 1 ) - Please choose one
Distortion occurs in a
___________ signal.
► Rectified
► Composite
► Amplified
► none of the given
Question No: 24 (
Marks: 1 ) - Please choose one
There are ________ basic
categories of multiplexing.
► 3
► 4
► 2
► 5
Question No: 25 (
Marks: 1 ) - Please choose one
In bit ____________, MUX adds
extra bits to a device.
► Stuffing
► Adding
► Multiplication
► Exchanging
Question No: 26 (
Marks: 1 ) - Please choose one
The local loop has
___________ cable that connects the subscriber telephone to the nearest end
office.
► Twisted-pair
► Coaxial
► Fiber-optic
► None of the given
Question No: 27 (
Marks: 1 ) - Please choose one
FTTC
stands for _____________
► flexible to the curb
► fiber to the curb
► fiber to the cable
► fiber to the center
Question No: 28 (
Marks: 1 ) - Please choose one
If
the ASCII character G is sent and the character D is received, what type of
error is this?
► Single-bit
► Multiple-bit
► Burst
► Recoverable
Question No: 29 (
Marks: 1 ) - Please choose one
Which error detection method
can detect a single-bit error?
► Simple parity check
► Two-dimensional parity check
► CRC
► All of the given
Question No: 30 (
Marks: 1 ) - Please choose one
Flow control is needed to
prevent ____________
► Bit errors
► Overflow of the sender buffer
► Overflow of the receiver buffer
► Collision between sender and receiver
Question No: 31 (
Marks: 1 ) - Please choose one
In data link layer,
communication requires at least ___________ devices working together
► 3
► 2
► 4
► 5
Question No: 32 (
Marks: 1 ) - Please choose one
Data link control is composed
of ____________ important functions.
► 2
► 3
► 4
► 5
Question No: 33 (
Marks: 1 ) - Please choose one
____________ coordinates the
amount of data that can be sent before receiving acknowledgment
► flow control
► error control
► data control
Question No: 34 (
Marks: 1 ) - Please choose one
Primary device uses
____________ to receive transmission from the secondary devices.
► ACK
► ENQ
► POLL
Question No: 35 (
Marks: 1 ) - Please choose one
In a
Go-Back-N ARQ, if the window size is 63, what is the range of sequence number?
► 0 to 63
► 0 to 64
► 1 to 63
► 1 to 64
Question No: 36 (
Marks: 1 ) - Please choose one
Data
link protocols can be divided into ______________ sub-groups.
► two
► three
► four
► five
Question No: 37 (
Marks: 1 ) - Please choose one
XMODEM
is a ______________ protocol designed for telephone-line communication b/w PCs.
► file transfer
► hardware
► software
► application exchange
Question No: 38 (
Marks: 1 ) - Please choose one
YMODEM uses ITU-T
CRC-_____ for Error Checking
► 16
► 32
► 8
► 4
Question No: 39 (
Marks: 1 ) - Please choose one
In Y-MODEM Multiple files can
be sent simultaneously
► True
► False
Question No: 40 (
Marks: 1 ) - Please choose one
HDLC
is an acronym for ______________.
► High-duplex line communication
► High-level data link control
► Half-duplex digital link combination
► Host double-level circuit
Question No: 41 (
Marks: 1 ) - Please choose one
What
is present in all HDLC control fields?
► P/F bit
► N(R)
► N(S)
► Code bits
Question No: 42 (
Marks: 1 ) - Please choose one
Which of the following
sublyer, resolves the contention for the shared media
► MAC
► LLC
► Phyical
Question No: 43 (
Marks: 1 ) - Please choose one
Ethernet
LANs can support data rates between _____________
► 1 and 100 Mbps
► 1 and 200 Mbps
► 1 and 500 Mbps
► 1 and 100 Gbps
Question No: 44 (
Marks: 1 ) - Please choose one
In FDDI, Token Passing is
used as Access method.
► True
► False
Question No: 45 (
Marks: 1 ) - Please choose one
Bridges
can divide a large ________ into smaller segments
► Network
► Packet
► Frame
► Address
Question No: 46 (
Marks: 1 ) - Please choose one
Like VRC, LRC and CRC,
Checksum is also based on _______________.
► Redundency
► Decimal Division
► Encryption
► Encoding
Question No: 47 (
Marks: 1 ) - Please choose one
Check sum method is used for
_______________ layers.
► Physical
► Application
► Transport
► Datalink
Question No: 48 (
Marks: 1 ) - Please choose one
Which of the following
___________ uses a series of filters to decompose multiplexed signal into its
constituent signals.
► Bridge
► MUX
► DEMUX
► Switch
Question No: 49 (
Marks: 1 ) - Please choose one
We need ____________ to
decompose a composite signal into its components.
► fourier transform
► nyquist theorem
► shannon capacity
Question No: 50 (
Marks: 1 ) - Please choose one
Data from computer is in
____________ form and the local loop handles _________ signals.
► Analog; analog
► Analog; digital
► Digital; digital
► Digital; analog
Question No: 51 (
Marks: 2 )
What is the formula to
calculate the number of redundancy bits required to correct a bit error in a
given number of data bits? [2]
Messages(frames) consist of m
data (message) bits, yielding an n=(m+r)-bit codeword.
Question No: 52 (
Marks: 2 )
What is R G rating of coaxial
cable?
Different
coaxial cable designs are categorized by their Radio government (
RG ) ratings
Each
cable defined by RG rating is adapted for a specialized function:
RG-8
- Used in Thick Ethernet
RG-9
- Used in Thick Ethernet
RG-11
- Used in Thick Ethernet
RG-58
- Used in Thin Ethernet
RG-59
- Used for TV
Question No: 53 (
Marks: 2 )
What are the advantages of
thin ethernet?
The
advantages of thin Ethernet are :
- reduced cost and
- ease of installation
Because the cable is lighter
weight and more flexible than that used in Thicknet
Question No: 54 (
Marks: 3 )
What is the difference
between a unicast, multicast, and broadcast address? [3]
Three methods can be used to transmit
packets over a network: unicast, multicast, and broadcast.
Unicast involves communication between a
single sender and a single receiver. This is a type of point-to-point
transmission; since the packet is transmitted to one destination at a time.
Multicast is used to send packets to a group
of addresses, represented by a "group address." In this case, packets
are transmitted from a single sender to multiple receivers. Since the same data
packet can be sent to multiple nodes by sending just one copy of the data, the
load of the sender and the overall load of the network are both reduced.
Broadcast involves sending packets to all
nodes on a network simultaneously. This type of transmission is used to
establish communication with another host, and for DHCP type methods of
assigning IP addresses.
Question No: 55 (
Marks: 3 )
T lines are designed for Digital data how they can be used
for Analog Transmission ?
T
Lines are digital lines designed for digital data however; they can also be
used for analog transmission (Telephone connections). Analog signals are first
sampled and the Time Multiplexed.
Question No: 56 (
Marks: 3 )
What are the three types of
Guided Media?
Guided
Media, are those media that provide a conduit from one device to another. Three types
are
- Twisted
pair cable
- Coaxial
cable
- Fiber-optic
Cable
Question No: 57 (
Marks: 5 )
Why do we need Inverse
Multiplexing? [5]
Data
& Video can be broken into smaller portions using Inverse Multiplexing and TX. An inverse multiplexer
(often abbreviated to "inverse mux" or "imux") allows a data stream to be broken into multiple
lower data rate communication links. An inverse multiplexer differs
from a demultiplexer in that each of the low
rate links coming from it is related to the others and they all work together
to carry their respective parts of the same higher rate data stream. By
contrast, the output streams from a demultiplexer may be completely independent
from each other and the demultiplexer does not have to understand them in any
way.
This is the opposite of a multiplexer which creates one high speed link
from multiple low speed ones.
It
can lease a 1.544 Mbps line from a common carrier and only use it fully for
sometime
Or
it can lease several separate channels of lower data rates
Voice can be sent
over any of these channels
Question No: 58 (
Marks: 5 )
Describe method of checksum
briefly?
The
sender subdivides data units into equal segments of ‘n’ bits(16 bits).These
segments are added together using one’s complement. The total (sum) is then
complemented and appended to the end of the original data unit as redundancy
bits called CHECKSUM. The extended data unit is transmitted across the network.
The receiver subdivides data unit as above and adds all segments together and
complement the result. If the intended data unit is intact, total value found
by adding the data segments and the checksum field should be zero. If the
result is not zero, the packet contains an error & the receiver rejects it
Question No: 59 (
Marks: 10 )
Explain Asynchronous Time
Division Multiplexing in detail? Also discuss its advantages over synchronous
TDM?
Asynchronous time-division
multiplexing (ATDM) is a method of sending information that resembles normal
TDM, except that time slots are allocated as needed dynamically rather than
preassigned to specific transmitters. ATDM is more intelligent and has better
bandwidth efficiency than TDM.
Time-division multiplexing
(TDM) is a type of digital or (rarely) analog multiplexing
in which two or more signals or bit streams are transferred apparently
simultaneously as sub-channels in one communication channel, but are physically
taking turns on the channel. The time domain is divided
into several recurrent timeslots of fixed length, one for each sub-channel. A
sample byte or data block of sub-channel 1 is transmitted during timeslot 1,
sub-channel 2 during timeslot 2, etc. One TDM frame consists of one timeslot
per sub-channel. After the last sub-channel the cycle starts all over again
with a new frame, starting with the second sample, byte or data block from
sub-channel 1, etc.
asynchronous time-division
multiplexing comprising receive circuits (CRl/i) supplying cells received via
input links, transmit circuits (CTl/j) transmitting retransmitted cells on
output links, a buffer memory (MT) storing the received cells and delivering
the cells to be retransmitted and a buffer memory addressing device (SMT)
including a write address source (SAE) and a read address source (fsl/j).
The switching unit further comprises a write
disabling circuit (pi) conditioned by a signal (adl) derived from the content
of at least one received cell or a signal (tle) derived from the absence of any
received cell and supplying a disabling signal (spi) and the address source
includes a disabling device (pac, pal) influenced by the disabling signal (spi)
so that no memory location is then occupied in the buffer memory (MT).
Advantages asynchronous TDM:
In asynchronous TDM, the timeslots
are not fixed. They are assigned dynamically as needed.
In order to reduce the communications costs in
time-sharing systems and multicomputer communication systems, multiplexing
techniques have been introduced to increase channel utilization. A commonly
used technique is Synchronous Time Division Multiplexing (STDM). In Synchronous
Time Division Multiplexing, for example, consider the transmission of messages
from terminals to computer, each terminal is assigned a fixed time duration.
After one user's time duration has elapsed, the channel is switched to another
user. With synchronous operation, buffering is limited to one character per
user line, and addressing is usually not required. The STDM technique, however,
has certain disadvantages. As shown in Figure 1, it is inefficient in capacity
and cost to permanently assign a segment of bandwidth that is utilized only for
a portion of the time. A more flexible system that efficiently uses the
transmission facility on an "instantaneous time-shared" basis could
be used instead. The objective would be to switch from one user to another user
whenever the one user is idle, and to asynchronously time multiplex the data.
With such an arrangement, each user would be granted access to the channel only
when he has a message to transmit. This is known as an Asynchronous Time
Division Multiplexing System (ATDM). A segment of a typical ATDM data stream is
shown in Figure 2. The crucial attributes of such a multiplexing technique are:1. An address is required for each transmitted message, and
2. Buffering is required to handle the random message arrivals.
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